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	<title>Comments on: Statistics of Breath Testing</title>
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	<link>http://blogs.gnome.org/jamesh/2006/05/16/statistics-of-breath-testing/</link>
	<description>Random stuff</description>
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		<title>By: Johannes</title>
		<link>http://blogs.gnome.org/jamesh/2006/05/16/statistics-of-breath-testing/comment-page-1/#comment-164</link>
		<dc:creator>Johannes</dc:creator>
		<pubDate>Wed, 30 Nov -0001 00:00:00 +0000</pubDate>
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		<description>Hi!&lt;p/&gt;Just for your notice. In Germany breath tests are only used for a fast investigation. You can only be judged if a blood test also gives a positive result. And of course, if people are slightly below the limit in the breath test, they do a blood test, too!&lt;p/&gt;Regards,&lt;br/&gt;Johannes</description>
		<content:encoded><![CDATA[<p>Hi!
<p />Just for your notice. In Germany breath tests are only used for a fast investigation. You can only be judged if a blood test also gives a positive result. And of course, if people are slightly below the limit in the breath test, they do a blood test, too!
<p />Regards,<br />Johannes</p>
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		<title>By: Olaf</title>
		<link>http://blogs.gnome.org/jamesh/2006/05/16/statistics-of-breath-testing/comment-page-1/#comment-165</link>
		<dc:creator>Olaf</dc:creator>
		<pubDate>Wed, 30 Nov -0001 00:00:00 +0000</pubDate>
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		<description>Hi James,&lt;p/&gt;assuming the device is unbiased (something that can easily be fixed if it where so by calibartion) you don&#039;t really need a more accurate method. All you need to to is average over several measurements. The mean of n measurements will again be normaly distributed, but with a variance of 1/n*sigma^2 if the original measurements had a variance of sigma^2. So by simply repeating the procedure you get a much lower margin of error. &lt;p/&gt;-- Olaf</description>
		<content:encoded><![CDATA[<p>Hi James,
<p />assuming the device is unbiased (something that can easily be fixed if it where so by calibartion) you don&#8217;t really need a more accurate method. All you need to to is average over several measurements. The mean of n measurements will again be normaly distributed, but with a variance of 1/n*sigma^2 if the original measurements had a variance of sigma^2. So by simply repeating the procedure you get a much lower margin of error.
<p />&#8211; Olaf</p>
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